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Sagot :
Answer:
2040cu.in
Step-by-step explanation:
first,
Given,. l= 10 in
b = 12 in
h = 20 in.
volume of whole fig with hollow part. = l X b X h
=. (10* 12 * 20)cu.in
= 2400 cu.in
and
volume by hollow part =( l-5)* b* (h- 14)
= (10-5)* 12* ( 20- 14)
=. 5 * 12 * 6
= 360 cu.in
Now ,
Volume of the given figure
= 2400 cu.in.- 360 cu.in
= 2040 cu.in
Answer:
Here maximum height = 20 in.
maximum length = 12 in.
maximum width = 10 in.
assume that it is a rectangular solid,
so the volume would be
= 20*12*10 [tex]in.^{3}[/tex]
= 2400 [tex]in.^{3}[/tex]
but we have to substrace upper portion
the length of the upper portion = 12 in.
the length of the upper portion = (10-5)in. = 5 in.
and height = (20-14)in. = 6 in.
so the volume of the missing portion
= 6*12*5 [tex]in.^{3}[/tex]
= 360 [tex]in.^{3}[/tex]
so the actual volume
= (2400-360) [tex]in.^{3}[/tex]
= 2040 [tex]in.^{3}[/tex]
answer : 2040 [tex]in.^{3}[/tex]
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