vladv009314
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PLEASE HELP 100 POINTS 100 100 100 PLEASSSSE
Adam has been caught speeding by a pair of average speed cameras. Te speed limit was 50 mph. The cameras are 2500 m apart.
The time was taken for his car to pass between them was 102 seconds.
a) What was Adam's average speed between the cameras?
Give your answer to the nearest mph. Take 1 mile as 1.6 km.
b) If Adam has been travelling within the speed limit, what us the minimum time it should have taken him to pass between the cameras? Give your answer to the nearest second.

Sagot :

lg48647

Answer:

b

Step-by-step explanation:

reinhard10158

Step-by-step explanation:

the distance is 2500 m = 2.5 km, which we have to change into miles by using the factor of 1.6.

so, 2.5 km / 1.6 = 1.5625 miles.

or in fractions

5/2 / 16/10 = 5/2 / 8/5 = 5/2 × 5/8 = 25/16 = 1 9/16 miles

Adam drove these 1.5625 miles in 102 seconds.

to get mph we need to transform 102 into 3600 (seconds in an hour).

102x = 3600

x = 3600/102 = 1800/51 = 600/17 = 35.29411765...

(25/16 / 102) × (600/17 / 600/17) =

(25×600 / 16×17) / (102×600 / 17) =

(25×75 / 2×17) / (6 × 600) = (1875 / 34) / 3600 =

55.14705882.../1 hour = 55.14705882... mph

a) Adam was driving 55 mph.

b) now we have to calculate backwards.

he would drive 50 miles in 3600 seconds, so, how many seconds for 25/16 miles ?

the factor is

50 / 25/16 = 50/1 × 16/25 = 50×16 / 25×1 = 2×16 = 32

he drove only 1/32 of the 50 miles.

so, now we need to divide 3600 by 32

3600 / 32 = 225/2 = 112.5 seconds

rounded it should have taken him at least 113 seconds.

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