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A ball rolls down a ramp for 5 seconds. It accelerated 3m/s2 until it reached 28 m/s. What was the ball’s initial velocity? (select the correct equation)

A Ball Rolls Down A Ramp For 5 Seconds It Accelerated 3ms2 Until It Reached 28 Ms What Was The Balls Initial Velocity Select The Correct Equation class=

Sagot :

genmad

Answer:

Option 4 is correct ,

Explanation:

By the question,

Time (t) = 5 sec

accelation (a) = 3m/s^2

final velocity (Vf) = 28m/s

we know that ,

[tex]a = \frac{vf - vi}{t} [/tex]

so, doing cross multiplication , we get:-

[tex]vf - vi = a \times t \\ vi = vf - a \times t \\ vi = 28 - (3 \times 5)[/tex]