Answered

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A local bank reports that 80% of its customers maintain a checking account, 60% of them
have a savings account, and 50% of them have both. If a customer is chosen at random,
what is the probability the customer has either a checking or a savings account? What is
the probability the customer has neither a checking nor a savings account?

Sagot :

Kittyhacker14

Answer:

(Hope this helps can I pls have brainlist (crown)☺️)

Step-by-step explanation:

In pic

View image Kittyhacker14
MrRoyal

The probability the customer has neither a checking nor a savings account is 10%

How to determine the probability?

The given parameters are:

P(checking account) = 80%

P(Savings account) = 60%

P(Both) = 50%

The probability that a customer has either of them is:

P(either) = 80% + 60% - 50%

Evaluate

P(either) = 90%

The probability that a customer has neither is:

P(Neither) = 1 - P(Either)

This gives

P(Neither) = 1 - 90%

Evaluate

P(Neither) = 10%

Hence, the probability the customer has neither a checking nor a savings account is 10%

Read more about probability at:

https://brainly.com/question/25870256

#SPJ6

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