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One of the largest helicopters in the world weighs 1 x 10^6 N. If you were to place this helicopter on a large piston of a hydraulic lift, what force would need to be applied to the small piston, with an area of .7 m^2, in order to lift the helicopter? The area of the large piston is 140 m^2.

( ^ means to the power of)

Sagot :

hamzaahmeds

This question involves the concepts of Pascal's Law and Pressure.

The required to be applied to the small piston is "5000 N".

According to Pascal's Law, the pressure applied to an incompressible fluid medium is equally transmitted in all directions. Hence, the pressure on each piston must be equal to each other:

[tex]P_1=P_2\\\\\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]

where,

F₁ = Force on small piston = ?

A₁ = Area of smaller piston = 0.7 m²

F₂ = Force on larger piston = weight of helicopter = 1 x 10⁶ N

A₂ = Area of larger piston = 140 m²

Therefore,

[tex]F_1=\frac{10^6\ N}{140\ m^2}(0.7\ m^2)[/tex]

F₁ = 5000 N

Learn more about Pascal's Law here:

https://brainly.com/question/14555269?referrer=searchResults

Attached picture shows Pascal's Law application on hydraulic lift.

View image hamzaahmeds
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