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Sagot :
This question involves the concepts of Pascal's Law and Pressure.
The required to be applied to the small piston is "5000 N".
According to Pascal's Law, the pressure applied to an incompressible fluid medium is equally transmitted in all directions. Hence, the pressure on each piston must be equal to each other:
[tex]P_1=P_2\\\\\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]
where,
F₁ = Force on small piston = ?
A₁ = Area of smaller piston = 0.7 m²
F₂ = Force on larger piston = weight of helicopter = 1 x 10⁶ N
A₂ = Area of larger piston = 140 m²
Therefore,
[tex]F_1=\frac{10^6\ N}{140\ m^2}(0.7\ m^2)[/tex]
F₁ = 5000 N
Learn more about Pascal's Law here:
https://brainly.com/question/14555269?referrer=searchResults
Attached picture shows Pascal's Law application on hydraulic lift.

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