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If a ball is thrown from a tall building, how tall is the building if it takes 6s for the ball to land?

Sagot :

AmaraDangTran

Answer:

the answer is 352.8m

Explanation:

Since the gravitational constant is denoted as g

[tex]g = 9.8 \: \frac{m}{ {s}^{2} }[/tex]

and the ball needed 6 seconds to land, so we can calculate the height of the building as:

[tex]h = 9.8 \: \frac{m}{ {s}^{2} } \times {(6s)}^{2} = 9.8 \: \frac{m}{ {s}^{2} } \times 36 {s}^{2} = 352.8m[/tex]

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