jackthejedi005
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sqdancefan

9514 1404 393

Answer:

  8/15

Step-by-step explanation:

The probability of 1 white counter in the two draws is ...

  p(1 white) = p(1st white & 2nd not) +p(1st not & 2nd white)

  = (6/10)(4/9) +(4/10)(6/9) = (24+24)/90 = 8/15

The probability that only one of the counters is white is 8/15.

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Alternate solution

There are 10C2 = 45 ways to draw 2 counters. Of these, there are 6C2 = 15 ways to draw 2 white counters, 4C2 = 6 ways to draw 2 non-white counters, and (6C1)(4C1) = 24 ways to draw 1 white counter. The probability of drawing 1 white counter in the two draws is 24/45 = 8/15.

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