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The probability of Jane wins a game is 7/10. Jane plays a game 50 times. Find the number of times she is expected to win the game.​

Sagot :

Answer:

35 times

Step-by-step explanation:

7/10 * 50 = 35

The number of times Jane is expected to win the game, when the probability of her to win the game is 7/10, is 35.

What is probability of an event?

Probability of an event is the ratio of number of favorable outcome to the total number of outcome of that event.

The probability of Jane wins a game is 7/10. The probability in percentage form is,

[tex]P=\dfrac{7}{10}\times100\\P=70\%[/tex]

Jane plays a game 50 times, in which 70% times she wins the game. Here, the number of times she is expected to win the game is equal to the 70% of 50. Thus,

[tex]n=50\times\dfrac{70}{100}\\n=35[/tex]

Thus, the number of times Jane is expected to win the game, when the probability of her to win the game is 7/10, is 35.

Learn more about the probability here;

https://brainly.com/question/24756209

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