Answered

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A sample of xenon gas occupies a volume of 5.24 L at 411 K. If the pressure remains constant, at what temperature will this
same xenon gas sample have a volume of 2.06 L?

Sagot :

Answer:

161.57 K

Explanation:

V1/T1 = v2/T2

(5.24 L)/(411 K) = (2.06 L)/T2

T2 = 161.57 K

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