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Sagot :
a.) 0.6g-0.339g=0.261g
(0.261g / 0.6g) x 100%= 43.5%
b.) (1 mol CoCl2 / 129.83 g) x (6.022 x 10^23 / 1 mol CoCl2)= 4.638 x 10^21
Part a.) uses knowledge about percent recovery and part b.) uses knowledge of converting 1 mol of a substance to formula units
A. The percentage of water, H₂O in the hydrate is 43.5%
B. The actual number of mole of water per formula unit CoCl₂ is 6 moles
A. How to determine the percentage of water
From the question given above, the following data were obtained:
- Mass of hydrate, CoCl₂•xH₂O = 0.6 g
- Mass of anhydrous, CoCl₂ = 0.339 g
- Mass of water = 0.6 – 0.339 = 0.261 g
- Percentage of water =?
Percentage of water = (mass of H₂O / mass of CoCl₂•xH₂O) × 100
Percentage of water = (0.261 / 0.6) × 100
Percentage of water = 43.5%
B. How to determine the mole of water per formula unit
To obtain the mole of water per formula unit CoCl₂, we shall determine the formula of the hydrate. This can be obtained as follow:
- Percentage of H₂O = 43.5%
- Percentage of CoCl₂ = 100 – 43.5 = 56.5
- Formula =?
Divide by their molar mass
CoCl₂ = 56.5 / 130 = 0.4
H₂O = 43.5 / 18 = 2.4
Divide by the smallest
CoCl₂ = 0.4 / 0.4 = 1
H₂O = 2.4 / 0.4 = 6
Thus, the formula of the hydrate is CoCl₂•6H₂O
Therefore, the mole of water per formula unit CoCl₂ is 6 moles
Learn more about mass composition:
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