At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Simplify 1c 1h1c 2 1r 2 class=

Sagot :

Answer:

[tex]\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}[/tex]

Step-by-step explanation:

[tex]\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}[/tex]

Combine [tex]\frac{1}{c} + \frac{1}{h}[/tex]

[tex]\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}[/tex]

Combine the bottom, too.

[tex]=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}[/tex]

Apply the fraction rule

[tex]=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}[/tex]

Cancel

[tex]=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}[/tex]

Therefore, [tex]\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}[/tex]

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.