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The bases on a softball diamond are 60 feet apart. How far is it from home plate to second base?

Sagot :

So use the pathagoris theorem. a^2+b^2=c^2 60 x 60 = 3600 so 3600 + 3600 = 72000 the square root of 7200 is 84.85 The distance between the home plate and the 2nd vase is 84.85 feet :)
rosygupt26

Answer:

84.85 feet apart

Step-by-step explanation:

a² + b² = c²

60² + 60² = c²

3600 + 3600 = 7200

[tex]\sqrt{7200}[/tex]

84.85 feet

:)

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