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Sagot :
Answer: approximately 4.74pKa is when you take the -log10 of your Ka. Therefore, taking the -log10(1.8*10-5), we get a value of approximately 4.74 for our pKa for acetic acid.
Explanation: hope this helps
The pKa of this acid is mathematically given as
pKa=4.74
What is the pka of this acid?
Question Parameter(s):
The acid dissociation constant, ka, of acetic acid is 1.8 x 10-5
Generally, the equation for the pKa is mathematically given as
pKa=-log( Ka).
Therefore
pKa=-log10(1.8*10-5)
pKa=4.74
In conclusion, the pKa of this acid
pKa=4.74
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