Answer:
Not applicable. Follow instructions in explanation please!
Step-by-step explanation:
I'm only working with what I can see, so if there's another thing being asked of you, please comment it so I can help!
I see you figured out this function starts at the origin already, so good job there! Mark your first point at (0, 0), because when x = 0, so does y. This is your x-intercept, y-intercept, and vertex (minimum value) (triple combo!) Next, what you'll want to do is find values an equal distance away from your vertex's x value (0) and plug them in, meaning in this case you want 1 & -1, and 2 & -2, because these will be equal in pairs, because your function is symmetrical. All parabolas are. So, for 1, y = 2(1)^2 = 2(1) = 2, so plot (1, 2) and (-1, 2) on your graph. For 2, y = 2(2)^2 = 2(4) = 8, so plot (2, 8) and (-2, 8) on your graph. This is all you have space for, but in general just 5 points should be enough to find a shape to draw an even, symmetrical curve through, so do that here!
Let me know if I missed anything or if you need a more thorough explanation of anything! I'm sorry it took so long for someone to get to you on this!
