3306414827
Answered

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A recursive rule for a geometric sequence is a1=9; an=2/3(an−1). What is the iterative rule for this sequence?

A.) an = 9 • (2/3)^n
B.) an = 2/3 • 9^n
C.) an = 9 • (2/3)^n-1
D.) an = 2/3 • 9^n-1

Sagot :

Step-by-step explanation:

C.) an=y

a1. (2/3)^ n-1

A1 = 4/9 n-1

a=4/9 * 9/9 n-1

A=4/1. N-1==> a=4-1n

A=3n

N=3

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