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Write in slope-intercept form an equation of the line that passes through the points (−15,−1) and (10,4).

Sagot :

Leora03

Answer:

[tex]y = \frac{1}{5} x + 2[/tex]

Step-by-step explanation:

Slope-intercept form

y= mx +c, where m is the slope and c is the y-intercept.

[tex]\boxed{slope = \frac{y1 - y2}{x1 - x2} }[/tex]

Slope

[tex] = \frac{4 - ( - 1)}{10 - ( - 15)} [/tex]

[tex] = \frac{4 + 1}{10 + 15} [/tex]

[tex] = \frac{5}{25} [/tex]

[tex] = \frac{1}{5} [/tex]

Substitute m= ⅕ into the equation:

y= ⅕x +c

To find the value of c, substitute a pair of coordinates.

When x= 10, y= 4,

4= ⅕(10) +c

4= 2 +c

c= 4 -2

c= 2

Thus, the equation of the line is y= ⅕x +2.

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