Answered

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(i) x²-3x = 0
(ii) x²+4x+4'= 0

Please solve this problem.​

Sagot :

SalmonWorldTopper

Step-by-step explanation:

Correction:

1⟩

Given equation is x²-3x = 4

⇛ x²-3x -4 = 0

⇛ x²+x-4x-4 = 0

⇛ x(x+1)-4(x+1) = 0

⇛ (x+1)(x-4) = 0

⇛ x+1 = 0 or x-4 = 0

⇛ x = -1 or x = 4

2.⟩

Given equation is x²+4x+4 = 0

⇛ x²+2x+2x+4 = 0

⇛ x(x+2)+2(x+2) = 0

⇛ (x+2)(x+2) = 0

⇛ x+2 = 0

⇛ x = -2

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