ShadowWolfie
Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Solve the equation with special factors. (Please show all steps)
16q^2 - 81 = 0

Sagot :

nikolavisinoski

Answer: [tex]q=\frac{\sqrt{81}}{16}[/tex]

Step-by-step explanation:

[tex]16q^2-81=0\\16q^2=0+81=81\\16q=\sqrt{81} \\q=\frac{\sqrt{81}}{16}[/tex]

Answer:

q = ± [tex]\frac{9}{4}[/tex]

Step-by-step explanation:

16q² - 81 = 0 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

16q² - 81 = 0

(4q)² - 9² = 0

(4q - 9)(4q + 9) = 0

Equate each factor to zero and solve for q

4q - 9 = 0 ⇒ 4q = 9 ⇒ q = [tex]\frac{9}{4}[/tex]

4q + 9 = 0 ⇒ 4q = - 9 ⇒ q = - [tex]\frac{9}{4}[/tex]

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.