Answered

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Solve Tan^2 theta= 1+sec theta

Sagot :

27tristenjones

Answer:sec0

Step-by-step explanation:

Answer:

sec θ = -1           θ = π+2nπ

sec θ = 2            θ = π/3+2nπ    or   5π/3+2nπ

Step-by-step explanation:

tan² θ = 1 + sec θ

sec² θ - 1 = 1 + sec θ

sec² θ - sec θ - 2 = 0

(sec θ + 1) (sec θ - 2) = 0

sec θ = -1           θ = π+2nπ

sec θ = 2            θ = π/3+2nπ    or   5π/3+2nπ

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