Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Calculate the amount of heat needed to convert 230.0 g of ice at -10.0ºC to liquid water at 10.0ºC.

Sagot :

pstnonsonjoku

The heat required to raise the temperature of ice from  -10.0ºC to 10.0ºC is 22.2 KJ.

The heat needed to convert 230.0 g of ice at -10.0ºC to liquid water at 10.0ºC is the sum of the latent heat of fusion of ice and the heat required to raise the temperature of the resulting water to.

Hence, the heat required is obtained from;

H = Heat required to raise the temperature from  -10.0ºC to 0ºC + Heat required to convert ice to water + Heat required to raise the temperature of water from 0ºC to 10.0ºC

H =[0.23 ×  2090 × (0 - (-10.0))] + [0.23 ×  33600] + [0.23 × 4186 × ( 10 - 0)]

H = 4807 + 7728 + 9627.8

H = 22.2 KJ

Learn more: https://brainly.com/question/20339399

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.