Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

According to the Rational Root Theorem, the following are potential roots of f(x) = 60x2 – 57x – 18.

Negative six-fifths, Negative one-fourths, 3, 6

Which is an actual root of f(x)?

Sagot :

27tristenjones

Answer:As for Rational Root Theorem, we substitute the given choices in the equation and if the value of f(x) is equal to 0 then, the certain choice is a root of the equation.

(1)     -6/5 :    f(x) = 60(-6/5)^2 - 57(-6/5) - 18  = 136.8

(2)     -1/4:     f(x) = 60(-1/4)^2 - 57(-1/4) - 18 = 0

(3)         3:     f(x) = 60(3)^2 - 57(3) - 18 = 351

(4)         6:     f(x) = 60(6)^2 -57(6) - 18 = 1800

Thus, the answer is the second choice.

Step-by-step explanation:

quint1836

Answer:

B -1/4

Step-by-step explanation:

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.