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Given the equation: (1 – 3k) x^2 + 3x – 4 = 0 determine the value of “k” that will give two Real roots.

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abidemiokin

The value of “k” that will give two real roots is 25/48

Given the equation  (1 – 3k) x^2 + 3x – 4, for the equation to have two real roots, this means that b^2 - 4ac > 0

From the given expression

a = 1 - 3k

b = 3

c = -4

Substitute into the equation b^2 - 4ac = 0

3^2 - 4(1 - 3k)(-4) = 0

9 + 16 (1-3k) = 0

9 + 16 - 48k =0

25 = 48k

k = 25/48

Hence the value of “k” that will give two real roots is 25/48

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