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Sagot :
we have
[tex]\begin{gathered} y \geq -3x + 1 \\ \\ y \leq \frac{1}{2} x+3 \end{gathered}[/tex]
using a graph tool
see the attached figure
The solution of the system is the shaded area
we know that
The line is solid
The line passes through points (0,1) and is shaded above the line.
[tex]y \leq \frac{1}{2} x+3[/tex]
The line is solid
The line passes through points (-2,2) and (0,3)and is shaded below the line
The two lines intersect at one point
therefore the answer is the option
B) Graph of two lines that intersect at one point. Both lines are solid. One line passes through points negative 2, 2 and 0, 3 and is shaded below the line. The other line passes through points 0, 1 and 1, negative 2 and is shaded above the line.
[tex]{\blue{\rule{25pt}{1pt}{\pink{\rule{30pt}{3pt}{\red{\rule{100pt}{5pt}{\blue{\rule{25pt}{1pt}{\pink{\rule{30pt}{3pt} }}}}}}}}}}[/tex][tex]{\blue{\rule{25pt}{1pt}{\pink{\rule{30pt}{3pt}{\red{\rule{100pt}{5pt}{\blue{\rule{25pt}{1pt}{\pink{\rule{30pt}{3pt} }}}}}}}}}}[/tex][tex]{\blue{\rule{25pt}{1pt}{\pink{\rule{30pt}{3pt}{\red{\rule{100pt}{5pt}{\blue{\rule{25pt}{1pt}{\pink{\rule{30pt}{3pt} }}}}}}}}}}[/tex]
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