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Sagot :
There is the concept that some genes are not always identical in their alleles. One allele may be dominant while the other may be recessive. This is also referred to as the heterozygous state. The number of heterozygous in a population can be calculated using the formulas: p + q= 1 and p^{2} + 2pq + q^{2} = 1
The percentage of the population expected to be heterozygous would be 48% (option c)
if 35% of the population has black fur which is recessive, q^{2} = 0.35 (35/100)
and q= \sqrt{0.35} = 0.5916
since p + q = 1 and q = 0.5916
p = 1 - 0.5916 = 0.4084
From the equation p^{2} + 2pq + q^{2} = 1
2pq represent the heterozygous population
2pq = 2 x 0.5916 x 0.4084
= 0.4832 ~ 0.48 = 48%.
Learn more: https://brainly.com/question/16694166
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