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10. A small helium tank claims to be able to fill 30 balloons to a volume of 3.15 L
at a pressure of 101 kPa. How many liters of helium will the tank be able to
produce at a pressure of 94.2 kPa? Assume that the temperature of the tank
remains the same throughout.

Sagot :

CintiaSalazar

Taking into account the Boyle's law, 3.377 L of helium the tank will be able to  produce at a pressure of 94.2 kPa.

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature, and moles.

Boyle's law is one of the gas laws that relates the volume and pressure of a certain quantity of gas kept at constant temperature.

This law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases; while if the pressure decreases, the volume increases.

Mathematically, Boyle's law states that the product of pressure and volume is constant:

P×V= k

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

P1× V1= P2×V2

In this case, you know:

  • P1= 101 kPa
  • V1= 3.15 L
  • P2= 94.2 kPa
  • V2= ?

Replacing in Boyle's law:

101 kPa× 3.15 L= 94.2 kPa× V2

Solving:

[tex]V2=\frac{101 kPa x3.15 L}{94.2 kPa}[/tex]

V2= 3.377 L

In summary, 3.377 L of helium the tank will be able to  produce at a pressure of 94.2 kPa.

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