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Sagot :
The vertices of a square are its endpoints
The coordinates of the other pairs are: (-1, 3), (4, 3) and (-1, -7), (4, -7)
The given parameters are:
[tex]\mathbf{E = (-1,-2)}[/tex]
[tex]\mathbf{F = (4,-2)}[/tex]
Calculate the distance EF
[tex]\mathbf{EF = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}[/tex]
So, we have:
[tex]\mathbf{EF = \sqrt{(-1 - 4)^2 + (-2 - -2)^2}}[/tex]
[tex]\mathbf{EF = \sqrt{25}}[/tex]
[tex]\mathbf{EF = 5}[/tex]
Add 5 to the y-coordinates of E and F
[tex]\mathbf{C = (-1,-2+5)}[/tex]
[tex]\mathbf{C = (-1,3)}[/tex]
[tex]\mathbf{D = (4,-2+5)}[/tex]
[tex]\mathbf{D = (4,3)}[/tex]
Subtract 5 to the y-coordinates of E and F
[tex]\mathbf{C = (-1,-2-5)}[/tex]
[tex]\mathbf{C = (-1,-7)}[/tex]
[tex]\mathbf{D = (4,-2-5)}[/tex]
[tex]\mathbf{D = (4,-7)}[/tex]
Hence, the coordinates of the other pairs are: (-1, 3), (4, 3) and (-1, -7), (4, -7)
There is no third pair
Read more about vertices at:
https://brainly.com/question/2791243
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