Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

find the derivative of h(x)=2x^4cotx/3x^2
is there a better way to do this using the quotient rule? this feels wrong

Find The Derivative Of Hx2x4cotx3x2 Is There A Better Way To Do This Using The Quotient Rule This Feels Wrong class=

Sagot :

LammettHash

If you want to avoid using the quotient rule, you can cancel the powers of x :

[tex]h(x) = \frac{2x ^{4} \cot(x) }{3 {x}^{2} } = \frac{2}{3} {x}^{2} \cot(x) [/tex]

Then differentiate using the product rule.

[tex]h'(x)=\frac23\left(2x\cot(x)-x^2\csc^2(x)\right)[/tex]

[tex]h'(x)=\frac43x\cot(x)-\frac23x^2\csc^2(x)[/tex]

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.