dcasarez2005
Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

A log rolls down a hill. When first measured the speed of the log in 1.3 m/s, after 4 seconds its speed is 3.2 m/s. If the log has a mass of 220 kg, what is the
force?
N (Round to 2 significant figures)

Sagot :

Lanuel

The force acting on the log as it rolls down a hill is equal to 104.5 Newton.

Given the following data:

  • Initial velocity = 1.3 m/s
  • Time = 4 seconds
  • Final speed = 3.2 m/s
  • Mass = 220 kg

To determine the force acting on the log:

First of all, we would calculate the acceleration of the log by using this formula:

[tex]Acceleration = \frac{V\;-\;U}{t} \\\\Acceleration = \frac{3.2\;-\;1.3}{4} \\\\Acceleration =\frac{1.9}{4}[/tex]

Acceleration = 0.475 [tex]m/s^2[/tex]

Now, we can solve for the force by applying Newton's Second Law of Motion:

[tex]Force = mass \times acceleration[/tex]

[tex]Force = 220 \times 0.475[/tex]

Force = 104.5 Newton

Read more here: https://brainly.com/question/24029674

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.