dcasarez2005
Answered

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A log rolls down a hill. When first measured the speed of the log in 1.3 m/s, after 4 seconds its speed is 3.2 m/s. If the log has a mass of 220 kg, what is the
force?
N (Round to 2 significant figures)

Sagot :

Lanuel

The force acting on the log as it rolls down a hill is equal to 104.5 Newton.

Given the following data:

  • Initial velocity = 1.3 m/s
  • Time = 4 seconds
  • Final speed = 3.2 m/s
  • Mass = 220 kg

To determine the force acting on the log:

First of all, we would calculate the acceleration of the log by using this formula:

[tex]Acceleration = \frac{V\;-\;U}{t} \\\\Acceleration = \frac{3.2\;-\;1.3}{4} \\\\Acceleration =\frac{1.9}{4}[/tex]

Acceleration = 0.475 [tex]m/s^2[/tex]

Now, we can solve for the force by applying Newton's Second Law of Motion:

[tex]Force = mass \times acceleration[/tex]

[tex]Force = 220 \times 0.475[/tex]

Force = 104.5 Newton

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