ericklivingston
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The trapezoid below has legs with lengths y feet and one base that is four feet longer than the other base, x.
A.) The perimeter of this trapezoid is given by P=2x + 2y + 4. Solve this equation for the leg length, y.
B.) If the perimeter of the figure is 26 feet and the shorter base, x, is 8 feet, then find the length of the leg, y.

Sagot :

abidemiokin

The equation for the leg length, y is y = (P - 2x - 4)/2

The length of the leg "y" is 3 feet

a) Given the perimeter of the trapezoid expressed as:

P=2x + 2y + 4.

We are to make y the subject of the formula as shown:

P = 2(x+y) + 4

P - 2x = 2y + 4

P - 2x - 4 = 2y

Swap

2y = P - 2x - 4

y = (P - 2x - 4)/2

Hence the equation for the leg length, y is y = (P - 2x - 4)/2

b) Give that P = 26 feet and x = 8feet

y = (P - 2x - 4)/2

y = (26 - 2(8) - 4)/2

P = 26-20/2

P = 6/2

y = 3 feet

This shows that the length of the leg "y" is 3 feet

Learn more here: https://brainly.com/question/18370541

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