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Sagot :
Answer:
2.8m/s (for slightly different values in the question but same concept)
Explanation:
The image below depicts a solution to the variation of this question but if you use the values you have been given and substitute it into the equations you should get the correct answer to your answer. This question is based on the conservation of momentum.
The speed of the 30-ton and 90-ton cars relative to the ground is 3 meters per second and 1 meter per second.
What is momentum?
The momentum of a mass will remain constant unless there is an external force acting on it. The momentum equation is given as
P = mv
Where m is mass and v is velocity.
A 30-ton rail car and a 90-ton rail car, initially at rest, are connected together with a giant but massless compressed spring between them.
When released, the 30-ton car is pushed away at a speed of 4.0 m/s relative to the 90-ton car.
Let v₁ be the velocity of a 30-ton rail car and v₂ be the velocity of a 90-ton rail car. Then we have
v₁ + v₂ = v
v₁ + v₂ = 4
v₂ = 4 – v₁
m₁ = 30 tons = 27215.5 kg
m₂ = 90 tons = 81646.6 kg
Then the conservation of the momentum, we have
m₁v₁ = m₂v₂
27215.5 × v₁ = 81646.6 × (4 – v₁)
v₁ (27215.5 + 81646.6) = 326586.4
v₁ = 3
Then
v₂ = 4 – v₁
v₂ = 4 – 3
v₂ = 1
More about the momentum link is given below.
https://brainly.com/question/4956182
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