changejc46
Answered

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Use nCk = [tex]\frac{n!}{k! (n-k)}[/tex]


How many different combos of 6 children can fit on 4 chairs?


[?] ways

Sagot :

Answer:

15 ways

Step-by-step explanation:

[tex]\frac{6!}{4!(6-4)!}=\frac{6!}{4!2!}=15[/tex]

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