Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

How many ways are there for eight men and five women to stand in a line so that no two women stand next to each other

Sagot :

Answer:

609638400 ways

Step-by-step explanation:

For 8 men in a line: 8! = 40320

  O   O   O   O   O   O   O   O  

1     2    3    4   5    6   7     8   9 ... in order to separate 2 women, there are 9 vacant places for 5 women, we have to choose 5 out of 9

C(9,5) = 9! / 5!4! = 126

Random place 5 women in the 5 chosen places: 5! = 120

Total ways: 40320 * 126 * 120 = 609638400

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.