Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

How many ways are there for eight men and five women to stand in a line so that no two women stand next to each other

Sagot :

Answer:

609638400 ways

Step-by-step explanation:

For 8 men in a line: 8! = 40320

  O   O   O   O   O   O   O   O  

1     2    3    4   5    6   7     8   9 ... in order to separate 2 women, there are 9 vacant places for 5 women, we have to choose 5 out of 9

C(9,5) = 9! / 5!4! = 126

Random place 5 women in the 5 chosen places: 5! = 120

Total ways: 40320 * 126 * 120 = 609638400

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.