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Sagot :
Increasing the daily spending from $16 to $16.80 would mean that the number of burgers sold would will increase by 37.
- N = 1000 + 210x - 5x²
- N = number of burgers sold
- x = daily spending
At x = $16.00
Number of burgers sold would be:
N = 1000 + 210(16) + 5(16²)
N = 1000 + 3360 - 1280
N = 3080 burgers
At x = $16.80 :
Number of burgers that would be sold :
N = 1000 + 210(16.80) + 5(16.80²)
N = 1000 + 3528 - 1411.2
N = 3116.8 burgers
Therefore, the Increase in the number of burgers sold :
- (3116.8 - 3080) = 36.8 burgers
Learn more :https://brainly.com/question/25381260
The number of hamburgers the restaurant will sell if it increases its daily spending on advertising from $17 to $17.80 is 32 more hamburgers.
This question wants us to use the differential method to estimate the number of hamburgers the restaurant will sell if it increases its daily spending on advertising from $17 to $17.80.
Given that;
- McDonalds sell N hamburgers where N = 1000 + 210x - 5x²
The differential for the above equation:
- [tex]\mathbf{\dfrac{dN}{dx} = \dfrac{d}{dx}\Big( 1100 + 210 -5x^2 \Big)}[/tex]
- [tex]\mathbf{\dfrac{dN}{dx}= 210 - 10x }[/tex]
Suppose x is increased by $Δx, we can then infer that the increase in ΔN in N can be computed as:
- ΔN ≅ N'(x) × Δx
- ΔN = (210 -10) × Δx
where;
- Δx = 17.80 - 17.00
- Δx = 0.8
∴
- ΔN = (210 -10) × 0.80
- ΔN = 40 × 0.8
- ΔN = $32
Therefore, we can conclude that the number of hamburgers the restaurant will sell if it increases its daily spending on advertising from $17 to $17.80 is 32 more hamburgers.
Learn more about differential method here:
https://brainly.com/question/18252932?referrer=searchResults
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