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After spending $x in advertising per day, a McDonalds restaurant finds that it sells N hamburgers where N = 1000 + 210x − 5x 2 . Estimate using differentials how many m

Sagot :

fichoh

Increasing the daily spending from $16 to $16.80 would mean that the number of burgers sold would will increase by 37.

  • N = 1000 + 210x - 5x²

  • N = number of burgers sold

  • x = daily spending

At x = $16.00

Number of burgers sold would be:

N = 1000 + 210(16) + 5(16²)

N = 1000 + 3360 - 1280

N = 3080 burgers

At x = $16.80 :

Number of burgers that would be sold :

N = 1000 + 210(16.80) + 5(16.80²)

N = 1000 + 3528 - 1411.2

N = 3116.8 burgers

Therefore, the Increase in the number of burgers sold :

  • (3116.8 - 3080) = 36.8 burgers

Learn more :https://brainly.com/question/25381260

ajeigbeibraheem

The number of hamburgers the restaurant will sell if it increases its daily spending on advertising from $17 to $17.80 is 32 more hamburgers.

This question wants us to use the differential method to estimate the number of hamburgers the restaurant will sell if it increases its daily spending on advertising from $17 to $17.80.

Given that;

  • McDonalds sell N hamburgers where N = 1000 + 210x - 5x²

The differential for the above equation:

  • [tex]\mathbf{\dfrac{dN}{dx} = \dfrac{d}{dx}\Big( 1100 + 210 -5x^2 \Big)}[/tex]
  • [tex]\mathbf{\dfrac{dN}{dx}= 210 - 10x }[/tex]

Suppose x is increased by $Δx, we can then infer that the increase in ΔN in N can be computed as:

  • ΔN ≅ N'(x) × Δx
  • ΔN = (210 -10) × Δx

where;

  • Δx = 17.80 - 17.00
  • Δx = 0.8

∴

  • ΔN = (210 -10) × 0.80
  • ΔN = 40 × 0.8
  • ΔN = $32

Therefore, we can conclude that the number of hamburgers the restaurant will sell if it increases its daily spending on advertising from $17 to $17.80 is 32 more hamburgers.

Learn more about differential method here:

https://brainly.com/question/18252932?referrer=searchResults

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