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When 10.8 g of Silver was reacted with Sulfur, 12.4 grams of product was produced (there was only one product). What is the empirical formula of the product?

Sagot :

Answer:

Ag2S

Explanation:

10.8 gm of silver, 12.4 gm of silver sulfide, so 12.4 -10.8 = 1,6 gm of sulfur

silver atomic weight is 108, sulfur atomic weight is 32  so

10.8/108;   = 0.10 mole Ag  1.6/32 = 0.05 mole sulfur

so there is a 2:1 ratio of silver to sulfur, so the compound is 2 silver 1 sulfur or Ag2S

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