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g One tank of gasoline has an octane rating of 130 and another tank of gasoline has an octane rating of 90. To obtain a mixture of 80 gallons with an octane rating of 115, how many gallons should be used from the tank with the octane rating of 90

Sagot :

30 gallons were used from the tank with the octane rating of 90.

Volume calculation

The used volume of the two tanks is unknown, so we can call x the volume of the 90 tank and y the volume of the 130 tank.

From this we can perform the following expression:

                                    [tex]x \times 90 + y \times 130 = 80 \times 115[/tex]

                                            [tex]9x + 13y = 920[/tex]     [1]

As the sum of the two volumes should give the final volume, we have:

                                             [tex]x + y = 80[/tex] [2]

Substituting the y value of expression 2 into expression 1 we have:

                                       [tex]9x + 13 (80-x) = 920[/tex]

                                                [tex]4x = 120[/tex]

                                                  [tex]x = 30[/tex]

So, 30 gallons were used from the tank with the octane rating of 90.

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