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Find two triangles with the given angle measure and side lengths. Round side lengths to the nearest tenth and angle measures to the nearest degree.
A = 61°, a = 14, b = 15

Sagot :

raytheweirdkid

Answer:

its A

Step-by-step explanation:

b^2 = 6^2 + 11^2 - 2*6*11cos 109  =   199.97

b =  14.1  to nearest tenth.

now use sine rule to find the value of < A

14.14 / sin 109 = 6 /  sin A

<A =  24 degrees

<C = 180 - 24 - 109  = 47 degrees

<3
The right answer is A
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