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Match its group with its percentage or mean Using
Number
Fish length
Description
to the nearest Inch
12
Adult
1
N
5
Juvenile
3
3
Juvenile
4
5
Adult
5
un
8
Adult
6
N
2
Juvenile
7
10
Adult
8
9
Juvenile
9
4
Juvenile
10
4
Juvenile
10.0
40.0
60.0
1. mean length of all fish in the sample
2. mean length of adult fish in the sample
3. mean length of juvenile fish in the sample
4. percentage of sample that were adult fish
5. percentage of sample that were juvenile fish
6. percentage of sample that were juveniles over 8 inches long
8.75
6.2
4.5

Match Its Group With Its Percentage Or Mean Using Number Fish Length Description To The Nearest Inch 12 Adult 1 N 5 Juvenile 3 3 Juvenile 4 5 Adult 5 Un 8 Adult class=

Sagot :

Desperada

(1)

Mean length of all fish in the sample - [tex]\boxed{\sf{\red{6.2}}}[/tex]

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

= 6.2

(2)

Mean length of adult fish in the sample - [tex]\boxed{\sf{\red{8.75}}}[/tex]

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

= 8.75

(3)

Mean length of juvenile fish in the sample - [tex]\boxed{\sf{\red{4.5}}}[/tex]

Mean = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

= 4.5

(4)

Percentage of sample that were adult fish - [tex]\boxed{\sf{\red{40}}}[/tex]

Percentage = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

% = 40

(5)

Percentage of sample that were juvenile fish - [tex]\boxed{\sf{\red{60}}}[/tex]

Percentage = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

% = 60

(6)

Percentage of sample that were juveniles over 8 inches long - [tex]\boxed{\sf{\red{10}}}[/tex]

Percentage = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

% = 10

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