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what is the equation of a line that passes through the points (6, -6) and (−6,−8)?

Sagot :

Hello There!

First, let's find the slope using this formula:

m=[tex]\frac{y2-y1}{x2-x1}[/tex]

m=[tex]\frac{-8-(-6)}{-6-6}[/tex]

m=[tex]\frac{-8+6}{-6-6}[/tex]

m=[tex]\frac{-2}{-12}[/tex]

m=[tex]\frac{1}{6}[/tex]

So the slope is 1/6.

Now use the Point-Slope formula:

y-y1=m(x-x1)

y-(-6)=1/6(x-6)

y+6=1/6x-1

y=1/6x-1-6

y=1/6x-7

Therefore, our final answer is: [tex]y=\frac{1}{6} x-7[/tex]

Hope this helps you!

~Just a felicitous girlie

#HaveAnAwesomeDay

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