Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

A 20.0 g sample of aluminum (specific heat = 0.902) g-1 oC-1) with an initial temperature of 2.5°C is heated with 427 J of
energy. What is the final temperature of the sample?
O 72.3°C
O 23.7°C
0 26.2°C
0 74.8°C
O 24.9°C

A 200 G Sample Of Aluminum Specific Heat 0902 G1 OC1 With An Initial Temperature Of 25C Is Heated With 427 J Of Energy What Is The Final Temperature Of The Samp class=

Sagot :

drpelezo

Answer:

T(final) = 26.2°C (3 sig. figs.)

Explanation:

Q = m·c·ΔT

m = mass of sample of interest = 20.0g

c = specific heat of sample of interest = 0.902j·g⁻¹·C⁻¹

ΔT = Temperature change = T(final) - T(initial) = T(f) - 2.5°C

Q = 427 joules

Q = m·c·ΔT => = ΔT = Q/m·c => T(f) = Q/m·c + T(i) = (427j/20.0g·0.902j·g⁻¹·C⁻¹) + 2.5°C = 26.16962306°C (calc. ans.) ≅ 26.2°C (3 sig. figs.)

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.