Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Answer:
00167M.
Explanation:
1 ml of 1.00HCl contains 1/1000 moles HCl.
this is 0.001 mole
whenput in 60 ml of water, the concentration is
(1/1000)/(60/1000)
mutiply by 1000/1000
the answer is 1/60 = 00167M.
The new concentration of the solution in molarity is 0.016 M.
How we calculte molarity?
Molarity is define as the no. of moles of solute present in per liter of solution and for this question it will be calculated as:
M₁V₁ = M₂V₂, where
M₁ = molarity of HCl = 1 M
V₁ = volume of HCl = 1 mL
M₂ = molarity of water = ?
V₂ = volume of water = 60 mL
On putting all these values on the above equation, we get
M₂ = (1)(1) / (60) = 0.0166 M
Hence, required molarity is 0.016 M.
To know more about molarity, visit the below link:
https://brainly.com/question/26873446
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.
