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A solution is made by adding 1.00 mL of 1.00 M HCl to 60.0 mL water. What is the new concentration of the solution in molarity

Sagot :

Answer:

00167M.

Explanation:

1 ml of 1.00HCl contains 1/1000 moles HCl.

this is 0.001 mole

whenput in 60 ml of water, the concentration is

(1/1000)/(60/1000)

mutiply by 1000/1000

the answer is 1/60 = 00167M.

The new concentration of the solution in molarity is 0.016 M.

How we calculte molarity?

Molarity is define as the no. of moles of solute present in per liter of solution and for this question it will be calculated as:
M₁V₁ = M₂V₂, where

M₁ = molarity of HCl = 1 M

V₁ = volume of HCl = 1 mL

M₂ = molarity of water = ?

V₂ = volume of water = 60 mL

On putting all these values on the above equation, we get

M₂ = (1)(1) / (60) = 0.0166 M

Hence, required molarity is 0.016 M.

To know more about molarity, visit the below link:
https://brainly.com/question/26873446