Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Tyra put a certain amount of money into a savings account. Then she started to save the same amount each month. After 8 months, she had $1680. After a YEAR, she had $2200.

Write an equation in slope-intercept form ( y=mx+b ) that models this scenario:

How much is she saving per month?


How much did she start with?


Sagot :

She saved $130 per month and she started with $640.

A linear equation is in the form:

y = mx + b;

where y, x are variables, m is the slope of the line and b is the y intercept.

Let y represent the total money Tyra has after x months.

After 8 months, she had $1680, hence:

1680 = 8m + b        (1)

After 1 year (12 months), she had $2200, hence:

2200 = 12m + b        (2)

Solving equation 1 and 2 simultaneously gives:

m = 130, b = 640

Therefore she saved $130 per month and she started with $640.

Find out more at: https://brainly.com/question/13911928