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Find the sixth term in the sequence: 1, 3, 9, ...

Sagot :

Answer:

a₆ = 243

Step-by-step explanation:

There is a common ratio between consecutive terms , that is

3 ÷ 1 = 9 ÷ 3 = 3

This indicates the sequence is geometric with nth term

[tex]a_{n}[/tex] = a₁ [tex]r^{n-1}[/tex]

where a₁ is the first term and r the common ratio

Here a₁ = 1 and r = 3 , then

a₆ = 1 × [tex]3^{5}[/tex] = 1 × 243 = 243

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