Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Here is a sketch of y=x^2+bx+c The curve intersects

Here Is A Sketch Of Yx2bxc The Curve Intersects class=

Sagot :

Answer:

y = 18  and  x = -2

Step-by-step explanation:

y = x^2+bx+c   To find the turning point, or vertex, of this parabola, we need to work out the values of the coefficients b and c. We are given two different solutions of the equation. First, (2, 0).  Second, (0, -14). So we have a value (-14) for c. We can substitute that into our first equation to find b. We can now plug in our values for b and c into the equation to get its standard form. To find the vertex, we can convert this equation to vertex form by completing the square. Thus, the vertex is (4.5, –6.25). We can confirm the solution graphically     Plugging in  (2,0) :

y=x2+bx+c  

0=(2)^2+b(2)+c  

y=4+2b+c  

-2b=4+c  

b=-2+2c  

Plugging in  (0,−14) :

y=x2+bx+c  

−14=(0)2+b(0)+c  

−16=0+b+c  

b=16−c  

Now that we have two equations isolated for  b , we can simply use substitution and solve for  c .   y=x2+bx+c  16 + 2 = y   y = 18  and  x = -2

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.