Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

What mass in grams of dextrose (C 6H 12O 6) will be required to produce 3.00 L of a 0.35M aqueous solution

Sagot :

Answer:

1.05 X 180 = 189 gm of dextrose                                      

Explanation:

What mass in grams of dextrose (C 6 H 12 O 6) will be required to produce 3.00 L of a 0.35 M aqueous solution

the molar mass of (C 6 H 12 O 6)  is

(6 X 12) + (1 X 12) + (6 x 16) =

72 +12 + 96=

180 g/mol

we need 3 L x 0.35 moles/L =    1.05 moles of dextrose

so

1.05 X 180 = 189 gm of dextrose                                      

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.