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You have been keeping track of the outside temperature for a class project.
At noon, the temperature was 80°F.
At 5:00 p.m., the temperature was 64°F.

What was the percent change between the temperature at noon and the temperature at 5:00 p.m.?

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The percent change between the temperature at noon and the temperature at 5:00 p.m. is -20%

The percent change is the relative change between two quantities expressed in percentage.

Given that the At noon, the temperature was 80°F while At 5:00 p.m., the temperature was 64°F. Hence:

Percent change = [(64°F - 80°F) / 80°F] * 100%

Percent change = -20%

Therefore the percent change between the temperature at noon and the temperature at 5:00 p.m. is -20%

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