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if the leftmost digits of two multi-digit numbers are 6 and 9, can you tell which number is greater? explain.

Sagot :

saniakhadye

Answer:

9

Step-by-step explanation:

9>6

ex. 92>69

nine is greater than 6, meaning that if a number begins with a 9, it automatically means that it is bigger than a number beginning with a 6.

The two-digit number formed with tens place taken by 9 will be always greater than the two-digit number formed with tens place taken by 6.

What is the place value of a digit in a number?

The value of each digit in a number is known as the place value. The 5 in 350, for example, represents 5 tens, or 50, whereas the 5 in 5,006 represents 5 thousand, or 5,000. It is critical that children that while a digit can be the same, its value is determined by its position in the number.

Let the two of the multi-digit number be a two digit number.

Now, It is known that the left-most place in a two-digit number is always tens place. Therefore, if a two-digit number is formed by the tens place taken by 6 and the unit digit taken by any other number, then it will always be less than the two digit number formed by formed by the tens place taken by 9 and the unit digit taken by any other number.

Also, if the two numbers are 4 digit numbers, the four-digit number is formed by the thousand place taken by 6 and the other place taken by any other digit, then it will always be less than the four digit number digit number formed by formed by the thousand place taken by 9 and the other place digit taken by any other digit.

Hence, the two-digit number formed with tens place taken by 9 will be always greater than the two-digit number formed with tens place taken by 6.

Learn more about the Place Value here:

https://brainly.com/question/27734142

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