sgriffith354
Answered

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sinx cosx tanx secx cscx
I know it =tanx but I need to know how to get there​

Sagot :

Answer:

see explanation

Step-by-step explanation:

Using the identities

tan x = [tex]\frac{sinx}{cosx}[/tex] , sec x = [tex]\frac{1}{cosx}[/tex] , csc x = [tex]\frac{1}{sinx}[/tex] , then consider left side

sinxcosxtanxsecxcscx

= sinxcosx × [tex]\frac{sinx}{cosx}[/tex] × secxcscx ← cancel cosx on numerator/ denominator

= sinx × sinx × [tex]\frac{1}{cosx}[/tex] × [tex]\frac{1}{sinx}[/tex] ← cancel sinx on numerator/ denominator

= sinx × [tex]\frac{1}{cosx}[/tex]

= [tex]\frac{sinx}{cosx}[/tex]

= tan x

= right side , thus proven

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