Answered

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what are the zeros of the polynomial function ? f(x) = 2x (x-2) (1-x)

Sagot :

Answer:

The zeros are 0 ,2, and 1

Step-by-step explanation:

f (x) = 2x (x - 2) (1 - x)

set f(x) equal to y

y = 2x (x - 2) (1 - x)

solve when y is 0 because when y is 0 then it is an x-intercept

0 = 2x (x - 2) (1 - x)

separate all of the equations out

0 = 2x

0 = (x - 2)

0 = (1 - x)

solve for x for each equation

0 = 2x

  • divide both sides by 2
  • 0/2 = 0 and 2x/2 = x
  • 0 = x
  • x = 0

0 = (x - 2)

  • add 2 to both sides
  • 0 + 2 = 2 and (x - 2) + 2 = x
  • 2 = x
  • x = 2

0 = (1 - x)

  • subtract 1 from both sides
  • 0 - 1 = -1 and (1 - x) - 1 = -x
  • -1 = - x
  • multiply both sides by -1
  • -1 · -1 = 1 and -x · -1 = x
  • 1 = x
  • x = 1

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