Answered

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In the diagram shown below, ABC and ABF  BCD.
Prove: BF  CD

In The Diagram Shown Below ABC And ABF BCD Prove BF CD class=

Sagot :

It has been proven below that BF ║ CD.

    From the given diagram, we are told that;

ΔABF ≅ ΔBCD

      This means both triangles are congruent.

Now, in the two triangles, we can see that;

∠BAF ≅ ∠CBD

Because they are corresponding angles

    We also see that;

∠ABF ≅ ∠BCD

Because they are corresponding angles

Since point B is the midpoint of AC, then it means that;

AB = BC

          Thus, we can see that 2 corresponding angles are equal and the included corresponding side is also equal and as a result this fulfils the ASA Congruency Postulate.

Thus, for the fact that ∠ABF ≅ ∠BCD, it means that BF must be parallel to CD.

Read more at; https://brainly.com/question/25354248

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