Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Contestants on a game show spin a wheel with 242424 equally-sized segments. Most of those segments show different prize amounts, but 222 of them are labeled "bankrupt":Suppose that a contestant is going to spin the wheel twice in a row, and the outcome of one spin doesn't affect the outcome of future spins. What is the probability that NEITHER of the spins land on "bankrupt"?

Sagot :

fichoh

Using the principle of probability, the probability that the outcome of both spins does not land on "bankrupt" is 1/144

Given the Parameters :

  • Total Number of possible outcomes = 24
  • Number of outcomes labeled bankrupt = 2
  • Labels which aren't labeled bankrupt = 24 - 2 = 22

Recall :

  • P(A) = required outcome / Total possible outcomes

First spin :

  • P(not bankrupt) = 2 / 24 = 1/12

Second spin :

  • P(not bankrupt) = 2/24 = 1/12

P(neither lands on bankrupt) = 1/12 × 1/12 = 1/144

Therefore, the probability that neither lands on bankrupt is 1/144

Learn more : https://brainly.com/question/18405415

Answer:

.84

Step-by-step explanation:

got it right on kahn

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.