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Contestants on a game show spin a wheel with 242424 equally-sized segments. Most of those segments show different prize amounts, but 222 of them are labeled "bankrupt":Suppose that a contestant is going to spin the wheel twice in a row, and the outcome of one spin doesn't affect the outcome of future spins. What is the probability that NEITHER of the spins land on "bankrupt"?

Sagot :

fichoh

Using the principle of probability, the probability that the outcome of both spins does not land on "bankrupt" is 1/144

Given the Parameters :

  • Total Number of possible outcomes = 24
  • Number of outcomes labeled bankrupt = 2
  • Labels which aren't labeled bankrupt = 24 - 2 = 22

Recall :

  • P(A) = required outcome / Total possible outcomes

First spin :

  • P(not bankrupt) = 2 / 24 = 1/12

Second spin :

  • P(not bankrupt) = 2/24 = 1/12

P(neither lands on bankrupt) = 1/12 × 1/12 = 1/144

Therefore, the probability that neither lands on bankrupt is 1/144

Learn more : https://brainly.com/question/18405415

Answer:

.84

Step-by-step explanation:

got it right on kahn

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